Ijumaa, 12 Julai 2013

SOLUTION TO LAST WEEK'S FORM FOUR SERIES ONE QUESTIONS


SOLUTIONS TO FORM FOUR SERIES ONE WEEKLY QUESTIONS:
QN 1:;
solution
(a) Three significant figures 300.0
(b) Three decimal places 300.326

QN2:
solution
Rationalization of the denominator 
QN3:
(a) solution

(b) solution
QN4 (a) solution
Table of values for the function
 
(b) The domain and ranges for the relation are such that

QN5.
Solution:
Marks Class Marks(x) Frequency (f) f.x Cumulative Frequency
0-9 4.5 1 4.5 1
10-19 14.5 2 29 3
20-29 24.5 5 122.5 8
30-39 34.5 11 379.5 19
40-49 44.5 21 934.5 40
50-59 54.5 20 1090 60
60-69 64.5 17 1096.5 77
70-79 74.5 10 745 87
80-89 84.5 6 507 93
90-99 94.5 4 378 97
100-109 104.5 4 418 101
110-119 114.5 1 114.5 102
TOTAL

102 5819


(a)Histogram and Frequency Polygon see figure 1.
(b) The modal class refers to the class with the highest frequency which in this case is 40-49.
(c) Solution:
(d) Calculating the median
But before anything you should find the median class by calculating the middle term of the cumulative frequency which is usually the number which is equal to the half of the total of frequency or just above.
Which in this case 102/2 = 51
So we choose the class with a cumulative frequency of 60.
Hence the median class is 50-59
Histogram and Frequency Polygon

FREQUENCY POLYGON

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